declaration of 'void* operator new [](size_t)' has a different exception specifier - 代码天地

declaration of 'void* operator new [](size_t)' has a different exception specifier

其他 2020-01-20 09:00:57 阅读次数: 0

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转载自www.cnblogs.com/fengtai/p/12216504.html

declaration of 'void* operator new [](size_t)' has a different exception specifier

error: this declaration has no storage class or type specifier

为什么operator new的第一个参数必须是size_t

C:error: expected declaration specifiers or ‘...’ before ‘size_t’

realloc(void *__ptr, size_t __size)函数

size_type、size_t、different_type以及ptrdiff_t

void *memset(void *str, int c, size_t n)

Symbol'' has different size in shared object,consider re-linking

已解决：Exception: Python in worker has different version 2.7 than that in driver 3.6

解决gcc的error: useless storage class specifier in empty declaration

cudaMallocHost(void **,size_t)”: 无法将参数 1 从“float **”转换为“void **”

void *mmap(void *start,size_t length,int prot,int flags,int fd,off_t offsize);

operator delete(void*) 和 operator new(unsigned long)未定义的问题

Symbol 'acs_map' has different size in shared object, consider re-linking

ImportError: 'module' object has no attribute 'check_specifier'

module 'setuptools.dist' has no attribute 'check_specifier'

A Java Exception has occurred

size_t总结

size_t

memcpy 、size_t

c size_t

浅析size_t

size_t类型

size_t 说明

神奇的 new Exception()

operator new/operator delete

Android dependency has different version for the compile and runtime

void operator()(){}

‘new’未声明(在此函数内第一次使用),对‘operator new[](unsigned long)’未定义的引用,对‘operator delete[](void*)’未定义的引用,

operator new和placement new

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