某安信笔试题目

第一题给的题目意思是输入两个数组,第一个数组是子线程(子节点),第二个数组是父线程(父节点),删除一个线程会删除此线程的所有子线程,问给出一个要删除的线程,总共要删除掉几个线程?

package test.test05;

import java.util.LinkedList;
import java.util.Queue;
import java.util.Scanner;

public class Main3
{
    public static void main(String[] args)
    {
        Scanner scanner = new Scanner(System.in);
        String a = scanner.nextLine();
        String b = scanner.nextLine();
        int temp = scanner.nextInt();
        String[] s1 = a.split(" ");
        int[] kids = new int[s1.length];
        for (int i = 0; i < s1.length; i++)
        {
            kids[i] = Integer.parseInt(s1[i]);
        }
        String[] s2 = b.split(" ");
        int[] parents = new int[s2.length];
        for (int i = 0; i < s2.length; i++)
        {
            parents[i] = Integer.parseInt(s2[i]);
        }
        scanner.close();
        Queue<Integer> queue = new LinkedList<>();
        queue.offer(temp);

        int length = parents.length;
        int count = 0;
        while (!queue.isEmpty())
        {
            temp = queue.poll();
            for (int i = 0; i < kids.length; i++)
            {
                if (parents[i] == temp && kids[i] != 0)
                {
                    queue.offer(kids[i]);
                }
            }
            count++;
        }
        System.out.println(count);

    }
}

在这里插入图片描述

package test.test05;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class Main2
{
    public static void main(String[] args)
    {
        Scanner sc = new Scanner(System.in);
        String s = sc.nextLine();
        char[] chars = s.toCharArray();
        int length = chars.length;
        int count = 0;
        Map<Character, Integer> map = new HashMap<>();
        ArrayList<Integer> list = new ArrayList<>();
        int i;
        for ( i = 0; i < length; i++)
        {
            for (int j = i; j < length  ; j++)
            {
                if (!map.containsKey(chars[j]))
                {
                    map.put(chars[j], null);
                    ++count;
                }else {
                    break;
                }
            }
            list.add(count);
            count = 0;
            map.clear();
        }
        int result = list.get(0);
        for (int k = 1; k < list.size(); k++)
        {
            if(list.get(k) >= result){
                result = list.get(k);
            }
        }
        System.out.println(result);
    }
}
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转载自blog.csdn.net/Funny_Ma/article/details/103865415
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