P5710 【深基3.例2】数的性质

https://www.luogu.com.cn/problem/P5710

#include<iostream>
using namespace std;
bool b[5];
bool ev(int n)
{
    if(n%2)
        return false;
    else 
        return true;
}
bool bi(int n)
{
    if(n>4&&n<=12)
        return 1;
    else 
        return 0;
}
int main()
{
    int x;
    cin >> x;
    b[1] = ev(x)&&bi(x);
    b[2] = ev(x)||bi(x);
    b[3] = (!ev(x)&&bi(x))||(ev(x)&&!bi(x));
    b[4] = !ev(x)&&!bi(x);
    for(int i = 1;i <= 4;i++)
        {
            cout << b[i] << " ";
        }

}

• 这是一道训练逻辑表达的C++题目

大佬

不使用函数更加简洁

#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;
int x;
bool a, b;
int main(){
    scanf("%d", &x);
    a = !(x & 1), b = (x > 4 && x <= 12);//a满足性质1，b满足性质2
    printf("%d %d %d %d", a & b, a | b, (a && !b || b && !a), !a && !b);
   //按条件输出就好啦QWQ
}