sh
count=1 while [ $count -le 5 ]; do echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS1 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS3 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS5 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS7 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS9 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS11 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS13 & echo 1234567890abcdefghqwertyuiopdasdk > /dev/ttyS15 & sleep 1 let count+=1 echo $count done
Linux shell while
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转载自www.cnblogs.com/chenfulin5/p/9055278.html
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