es6方法过滤掉两个数组中对象id值相等的项

方法1： 

let arr1=[{id:1,name:'老大'},{id:2,name:'老二'}] 
let arr2=[{id:1,name:'老大'},{id:3,name:'老三'},{id:4,name:'老四'},{id:5,name:'老五'},] 

let add=arr2.filter(item=>!arr1.some(ele=>ele.id===item.id)) 
console.log(add)

方法2：

const arr1 = [{ id: 1, name: '老大' }, { id: 2, name: '老二' }];
const arr2 = [{ id: 1, name: '老大' }, { id: 3, name: '老三' }];

// 获取到arr1的所有id集合
let arr1Ids = arr1.map(item => item.id);

// 过滤arr2中不包含arr1相同的id数组。
const result = arr2.filter(item => !arr1Ids.includes(item.id));
console.log(result);