删除链表的重复元素

/**
 * 给定一个排序链表,删除所有含有重复数字的节点,只保留原始链表中 没有重复出现 的数字。
 *
 * 示例 1:

 * 输入: 1->2->3->3->4->4->5
 * 输出: 1->2->5
 * 示例 2:

 * 输入: 1->1->1->2->3
 * 输出: 2->3
 * };
 */

class Solution {

	struct ListNode {
		ListNode*next;
		int val;
		ListNode(int n):val(n),next(NULL){}
	};
public:
	
	ListNode *deleteDuplicates(ListNode *head) {
		if (!head || !head->next) return head;

		ListNode *start = new ListNode(0);
		start->next = head;
		ListNode *pre = start;
		while (pre->next) {

			ListNode *cur = pre->next;

			while (cur->next && cur->next->val == cur->val)
			{
				cur = cur->next;
			}
			if (cur != pre->next) {
				//from 重复元素的开始位置,to 重复元素的下一个位置
				ListNode*from = pre->next;
				ListNode*to = cur->next;
				//断开连接
				pre->next = cur->next;
				//删除重复值
				while (from!= to) {
					ListNode*tmp = from;
					from = from->next;
					delete tmp;
				}
			}
			else {
				pre = pre->next;
			}
		}
		return start->next;
	}
};
/**
*给定一个排序链表,删除所有重复的元素,使得每个元素只出现一次。
*示例 1:
*输入: 1->1->2
*输出: 1->2
*
*示例 2:
*输入: 1->1->2->3->3
*输出: 1->2->3
*/
class Solution {
	struct ListNode {
		ListNode*next;
		int val;
		ListNode(int n) :val(n), next(NULL) {}
	};
public:
	ListNode *deleteDuplicates(ListNode *head) {
		if (!head || !head->next) return head;

		ListNode *start = head;
		while (start && start->next) {
			if (start->val == start->next->val) {
				ListNode *tmp = start->next;
				start->next = start->next->next;
				delete tmp;
			}
			else start = start->next;
		}
		return head;
	}
};
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转载自blog.csdn.net/mrbaolong/article/details/104392897