char 指针如何判断字符串需要输出长度

先上代码:

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 
 5 const char g_ip[32] = "123456789";
 6 int func1(const char *ip)
 7 {
 8         printf("ip:%s\n",ip);
 9         printf("ip size:%d\n",sizeof(ip));
10         if(*ip == '\0')
11                 printf("ip is none\n");
12         printf("g_ip:%s\n",g_ip);
13         printf("g_ip size:%d\n",sizeof(g_ip));
14         if(*ip == '\0')
15                 printf("g_ip is none\n");
16         return 0;
17 }
18 
19 int main()
20 {
21         const char ip[32]="ABCDEFG";
22         func1(ip);
23         return 0;
24 }

运行结果:

[zyc@localhost ~]$ ./a.out
ip:ABCDEFG
ip size:8
g_ip:123456789
g_ip size:32

看8、9行代码,为什么ip是一个char指针, 但是%s的时候却知道到底要printf多长???

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转载自www.cnblogs.com/fallenmoon/p/8979683.html