Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) B. Journey Planning（映射） - 代码天地

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) B. Journey Planning（映射）

其他 2020-03-18 20:34:13 阅读次数: 0

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转载自www.cnblogs.com/Kanoon/p/12519897.html

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) B. Journey Planning（映射）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) B. Journey Planning

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)B. Journey Planning

Codeforces Round #625 (Div. 1, based on Technocup 2020 Final Round).B. Navigation System

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)【A、B、C题】

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) D

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) C. Remove Adjacent（模拟）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)（A-C题解）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)Navigation SystemD(最短路+思维)

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) A. Contest for Robots（思维题）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)C. Remove Adjacent

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round)A. Contest for Robots

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) 总结

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) C.Remove Adjacent

Codeforces Round #625 (Div. 1, based on Technocup 2020 Final Round) D. Reachable Strings

Codeforces Round #625 (Div. 1, based on Technocup 2020 Final Round)

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) D. Navigation System（最短路）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) D - Navigation System（最短路 BFS）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) D. Navigation System（最短路spfa+思维）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) C. Remove Adjacent（贪心+暴力）

Codeforces Round #625 (Div. 2, based on Technocup 2020 Final Round) C. Remove Adjacent（字符串，贪心，枚举）

Codeforces Round #625 (Div. 1, based on Technocup 2020 Final Round)B（反向建图，BFS最短路）

Codeforces Round #625 (Div. 2) B. Journey Planning /详解

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