Use Linux's three loop structures to write scripts to print odd numbers within 10

1. Use while to print odd numbers within 10

#!/bin/bash

i=1

while [ $i -lt 11 ];do

[ $(($i%2)) -ne 0 ] && echo $i

((i++))

done

2. Use for to print odd numbers within 10

#!/bin/bash

for ((i=1;i<10;i=i+2));

do

echo $i

done

3. Use until to print odd numbers within 10

#!bin/bash
i=0
until [ "$i" -gt 99 ];do
    let i++
    if [ "$[i%2]" -eq 0 ];then
       continue    
    fi
    echo i=$i
done

ps:
-gt means big and
-eq means equal
-ne means not equal to
-ge means greater than or equal to
-lt means less than
-le means less than or equal to