Find the value of a+aa+aaa+aaaa+...+aaaaaaaaa(n a), n is a number - Code World

Find the value of a+aa+aaa+aaaa+...+aaaaaaaaa(n a), n is a number

Others 2021-02-26 16:42:58 views: null

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Origin blog.csdn.net/weixin_54748281/article/details/114011965

Find the value of a+aa+aaa+aaaa+...+aaaaaaaaa(n a), n is a number

Enter a number, find Sn = a + aa + aaa + aaaa + n Paragraph front and aaaaa

c Language practice 18-- find s = a + aa + aaa + aaaa + aa ... the value of a, where a is a number

OJ find the value of s=a+aa+aaa+aaaa+aa...a

Seeking s = a + aa + aaa + aaaa + aa ... the value of a, where a is a number.

(C language) Input two integers a and n, and calculate the value of the following expression. Sn=a+aa+aaa+aaaa+.....+aa..aa(n a)

Seeking Sn = a + aa + aaa + ... + aa ... aaa (with n a) of the value, where a is a number of 2. For example, n = 5 when = 2 + 22 + 222 + 2222 + 22222, n input from the keyboard.

Java title base algorithm (08): find s = a + aa + aaa + aaaa + aa ... the value of a, where a is a number. E.g. 2 + 22 + 222 + 2222 + 22222 (in this case the sum total of the number 5), a control keyboard a few numbers together.

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Find the sum of the first 5 terms of Sn=a + aa + aaa + aaaa + aaaaa, where a is a number

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That value of Number of n in number of n - and with a recursive function factorial Fibonacci

Find the sum of the first 5 terms of Sn=a+aa+aaa+aaaa+aaaaa, where a is a number, for example: 2+22+222+2222+22222

Find the sum of the first 5 terms of Sn=a+aa+aaa+aaaa+aaaaa, where a is a number, for example: 2+22+222+2222+22222

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