Python large number addition

Read in two numbers in the form of a string, write a function to calculate their sum, and return it in the form of a string.
(The length of the string is not greater than 100000, and it is guaranteed that the string is only composed of 10 characters from '0' to '9')

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
# 计算两个数之和
# @param s string字符串 表示第一个整数
# @param t string字符串 表示第二个整数
# @return string字符串
#
class Solution:
    def solve(self , s , t ):
        maxlen = len(s)
        if maxlen < len(t):
            maxlen = len(t)
        s = s.zfill(maxlen)
        t = t.zfill(maxlen)
        shiwei = 0
        sum = ''
        for i in range(-1,-maxlen-1,-1):

            temp= ord(s[i]) +ord(t[i]) - 96 + shiwei
            if temp >= 10:
                shiwei = 1
                temp = temp - 10
            else:
                shiwei=0
            sum+=str(temp)
        if shiwei != 0:
            sum+=str(shiwei)
        return sum[::-1]

Main key points

• zfill function use: right-aligned fill
• range(-1,-maxlen-1,-1): meaning, starting from the last bit
• The meaning of ord(s[i]) function; convert the string into ASCII code corresponding number, if it is a pure number, -48 is required
• [::-1] Meaning: output the string in reverse.

test:

s="733064366"
t="459309139"
print(s)
print(t)

maxlen = len(s)
if maxlen < len(t):
    maxlen = len(t)

s = s.zfill(maxlen)
t = t.zfill(maxlen)

print(s)
print(t)
# print(maxlen)
shiwei = 0
sum = ''
for i in range(-1,-maxlen-1,-1):
    #print(i)
    temp= ord(s[i]) +ord(t[i]) - 96 + shiwei
    if temp >= 10:
        shiwei = 1
        temp = temp - 10
    else:
        shiwei=0
    sum+=str(temp)
if shiwei != 0:
    sum+=str(shiwei)
print(sum[::-1])