dfs(P1036 [NOIP2002 普及组] 选数)

#include"bits/stdc++.h"

using namespace std;
int n,m,cnt;
int s[25];
bool ss(int x){
	for(int i=2;i<=sqrt(x);i++){
		if(x%i==0) return 0;
	}
	return 1;
}
// index 数字的下标  sum 累加的值  num 累加的次数 
void dfs(int index,int sum,int num)
{
	if(num == m){
		if(ss(sum)) cnt++;
		cout << sum << endl;
	}
	for(int i = index ; i <=n ; i++){
		dfs(i+1,sum+s[i],num+1);
	}
}
int main()
{
	cin >> n >> m;
	for(int i=1;i<=n;i++) cin >> s[i];
	dfs(1,0,0);
	cout << cnt << endl;	
	return 0;
 } 

不会dfs  看别的博主代码 慢慢学着写

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Origin blog.csdn.net/weixin_53013914/article/details/120619781