Question: Given an integer x, if x is a palindrome, return true; otherwise, return false. A palindrome is an integer that reads the same in forward order (left to right) and reverse order (right to left). For example, 121 is a palindrome, but 123 is not.
Example 1:
Input: x = 121
output: true
Example 2:
Input: x=-121
output: false
Example 3:
Input: x=10
output: false
bool isPalindrome(int x){
if(x < 0 || (x % 10 ==0 && x != 0)){
return false;
}
int revertedNumber = 0;
while(x > revertedNumber){
revertedNumber = revertedNumber * 10 + x % 10;
x /=10;
}
return x == revertedNumber || x == revertedNumber/10;
}
Code idea:
Call parameter x, if x is less than 0, return false, not a palindrome value, if the last digit of x value is 0, or x is equal to 0, return false, not a palindrome value, define reverteNumber as 0, when x is greater than 0 When the value of 12321 is divided by 10, the remainder is 1, and the division of x by 10 is equal to 1232, and the cycle continues.
