52d6c6af :
Why does the following not print two digits for the minutes and seconds?
Documentation for Intl.DateTimeFormat
.
Note that adding hour12: false
to the options for the hour, minute or second formatters has no visible effect.
const DTF = Intl.DateTimeFormat
const ye = (d) => new DTF('en-GB', { year: 'numeric' }).format(d)
const mo = (d) => new DTF('en-GB', { month: '2-digit' }).format(d)
const da = (d) => new DTF('en-GB', { day: '2-digit' }).format(d)
const ho = (d) => new DTF('en-GB', { hour: '2-digit' }).format(d)
const mi = (d) => new DTF('en-GB', { minute: '2-digit' }).format(d)
const se = (d) => new DTF('en-GB', { second: '2-digit' }).format(d)
const format = (d) => `${ye(d)}/${mo(d)}/${da(d)} ${ho(d)}:${mi(d)}:${se(d)}`
console.log(format(new Date('2019-01-01T00:00:00Z'))) // 2019/01/01 00:0:0
jcpaiva :
Just use formatToParts since that's a known issue.
const DTF = new Intl.DateTimeFormat('in', { year: 'numeric', month: '2-digit', day: '2-digit', hour: '2-digit', minute: '2-digit', second: '2-digit' })
const dp = DTF.formatToParts(new Date('2019-01-01T01:02:03Z'))
console.log(dp)
console.log(`${dp[4].value}/${dp[2].value}/${dp[0].value} ${dp[6].value}:${dp[8].value}:${dp[10].value}`)