Fun programming _ grab n game
Topic description
This is a Chinese folk game. Two people report numbers in turn starting from 1. Each person can report one number or two consecutive numbers at a time. Whoever reports to n first (n<1000000001) is the winner. Now it is up to you to decide whether the first hand wins or the second hand wins.
enter
There are multiple sets of data, each row has only one n;
output
If the first mover wins, output no, otherwise output yes;
sample input
10
Sample output
no
Code:
#include<stdio.h>
int main()
{
int n;
while(scanf("%d",&n)==1)
if(n%3==0)
printf("%s\n","yes");
else
printf("%s\n","no");
return 0;
}
int main()
{
int n;
while(scanf("%d",&n)==1)
if(n%3==0)
printf("%s\n","yes");
else
printf("%s\n","no");
return 0;
}