Transfer: http://blog.csdn.net/truong/article/details/46891525
Description of the problem: There is a problem in saving the database by entering "emoji expression" in the nickname of ipone5s.
Operating environment: Java, Tomcat, mysql, Linux (garbled characters under my Linux, this is a Linux problem)
Reason: emoji expressions of IOS 5.x and above are all 4 bytes, and utf8 in mysql has a maximum of 3 bytes per character. Therefore, if the database cannot be saved, the following error will be reported:
Caused by: java.sql.SQLException: Incorrectstring value: '\xF0\x9F\x8E\x80\xE5\xA4...' for column 'nickname' at row 1
Solution:
1. Remove emoji (this method is used)
2. Modify the Mysql data encoding. Now the utf8mb4 encoding in MySQL is extended to a maximum of 4 bytes per character (the existing database encoding needs to be modified, and this method is not used).
the first method:
"Remove emoji, java class:
"Call code: EmojiFilter.filterEmoji("nickname");
code
public class EmojiFilter {
/**
* Check if there are emoji characters
* @param source
* @return throws if it contains
*/
public static boolean containsEmoji(String source) {
if (StringUtils.isBlank(source)) {
return false;
}
int len = source.length();
for (int i = 0; i < len; i++) {
char codePoint = source.charAt(i);
if (isEmojiCharacter(codePoint)) {
//do nothing, it is judged here to indicate , confirm that there are emoji characters
return true;
}
}
return false;
}
private static boolean isEmojiCharacter(char codePoint) {
return (codePoint == 0x0) ||
(codePoint == 0x9) ||
(codePoint == 0xA) ||
(codePoint == 0xD) ||
((codePoint >= 0x20) && (codePoint <= 0xD7FF)) ||
((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) ||
((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));
}
/**
* 过滤emoji 或者 其他非文字类型的字符
* @param source
* @return
*/
public static String filterEmoji(String source) {
if (!containsEmoji(source)) {
return source;//If not included, return directly
}
//It must include
StringBuilder buf = null;
int len = source.length();
for (int i = 0; i < len; i++) {
char codePoint = source .charAt(i);
if (isEmojiCharacter(codePoint)) {
if (buf == null) {
buf = new StringBuilder(source.length());
}
buf.append(codePoint);
} else {
}
}
if (buf == null) {
return source;//If no emoji is found, return the source string
} else {
if (buf.length() == len) {//The meaning here is to have as little toString as possible, because the string will be regenerated
buf = null;
return source;
} else {
return buf.toString();
}
}
}
}