Write in C language to generate regular/inverted triangles of infinite length

During this period of time, I was busy studying, and I didn’t update the technical articles on the website. Today I will post one~

The project uses do while , if , for etc;

Project example:

#include <stdio.h>
int main(int scanfs) {
    int a;
    int hs;
    int ds,dd;
    do {
        scanf("%d", &a); // 输入自定义行数三角形
        scanf("%d",&scanfs); // 输入判断自行正三角形或倒三角形
        if (scanfs == 1) { // 判断成功后， 开始执行正三角形
            for (int b = 1; b <= a; b++) {
                for (int c = 2 * 10; c >= b; c--)
                    printf(" ");
                for (int c = 1; c <= 2 * b - 1; c++)
                    printf("*");
                printf("\n");
 
            }
        }
        /// 倒三角形
        if (scanfs == 2) {
            scanf("%d", &hs); // 判断是倒三角形后， 需要重新输入行数
            for (ds = 0; ds < hs; ds++) {
                for (dd = 0; dd < ds; dd++)
                    printf(" ");
                for (dd = hs - dd; dd > 0; dd--)
                    printf("* ");
                printf("\n");
            }
        }
    }
    while (scanfs != 1 && scanfs != 2); // 判断不是 1或2 ，重新执行 do 里的语句
    return 0;
}

No need to enter the number of inverted triangle rows twice:

#include <stdio.h>
int main(int scanfs) {
    int a;
    int hs;
    int ds,dd;
    do {
        scanf("%d", &a); // 输入自定义行数三角形
        scanf("%d",&scanfs); // 输入判断自行正三角形或倒三角形
        if (scanfs == 1) { // 判断成功后， 开始执行正三角形
            for (int b = 1; b <= a; b++) {
                for (int c = 2 * 10; c >= b; c--)
                    printf(" ");
                for (int c = 1; c <= 2 * b - 1; c++)
                    printf("*");
                printf("\n");
 
            }
        }
        /// 倒三角形
        if (scanfs == 2) {
//            scanf("%d", &hs); // 判断是倒三角形后， 需要重新输入行数
            for (ds = 0; ds < a; ds++) {
                for (dd = 0; dd < ds; dd++)
                    printf(" ");
                for (dd = a - dd; dd > 0; dd--)
                    printf("* ");
                printf("\n");
            }
        }
    }
    while (scanfs != 1 && scanfs != 2); // 判断不是 1或2 ，重新执行 do 里的语句
    return 0;
}

 

Execution effect: