**@Seeking 100000000! how many 0s at the end
/ Ask for 100000000! How many 0s at the end
can multiply two numbers to get 0?
It can only be 2 5 because the number of 2 is far more than 5
, so it is only necessary to count the number of 5
*/
#include <stdio.h>
int main()
{ int x = 5; int num; int sum = 0; for ( ; x <= 100000000; x = x + 5) { num = x; while (num % 5 == 0) { sum++; num = num / 5;
}
}
printf("%d\n",sum);
}**