Calculation python 1 to n odd, and

# Write a function that takes n and 1-n calculates and returns odd

def oddsum(n):
    sum=0
    for i in range(1,n+1):
        if(i%2==1):
            sum+=i
    return sum
n=(int)(input("请输入一个整数"))
print("1-"+str(n)+"中奇数和相加为"+str(oddsum(n)))

functions required based on the built sum to 1 and n is odd

num=[]
n=(int)(input("请输入一个整数"))
for i in range(1,n+1):
    if(i%2==1):
        num.append(i)
print(num)
print(sum(num))