Requirements: two realized subtracting dates, date and number of days an addition, subtraction.
#include<stdio.h>
#include<stdlib.h>
using namespace std;
class Date
{
public:
Date(){year=0;month=0;day=0;}
Date(int y,int m,int d){year=y;month=m;day=d;}
friend int operator *(Date &d1,Date&d2); ///友元重载函数
friend Date operator +(Date &d1,Date&d2);
friend Date operator -(Date &d1,Date&d2);
Date(int d) ///把Int型的数据转化成对象的格式。
{
year=d/360;
d=d%360;
month=d/30;
d=d%30;
day=d;
}
void display();
private:
int year,month,day;
};
Date operator+(Date &d1,Date &d2)
{
Date d3;
if((d1.day+d2.day)>30)
{d3.day=d1.day+d2.day-30;
d3.month=d1.month+d2.month+1;
}
else
{d3.day=d1.day+d2.day;
d3.month=d1.month+d2.month;
}
if(d3.month>12)
{
d3.month=d3.month-12;
d3.year=d1.year+d2.year+1;
}
else
d3.year=d1.year+d2.year;
return d3;
}
Date operator -(Date &d1,Date &d2)
{
Date d3;
if((d1.day-d2.day)<0)
{
d3.day=30+d1.day-d2.day;
d3.month=d1.month-d1.month-1;
}
else
{
d3.day=d1.day-d2.day;
d3.month=d1.month-d2.month;
}
if((d3.month)<0)
{
d3.month=12+d3.month;
d3.year=d1.year-d2.year-1;
}
else
{
d3.year=d1.year-d2.year;
}
return d3;
}
int operator*(Date &d1,Date&d2)
{
int a=(d1.year-1)*360+d1.month*30+d1.day;
int b=(d2.year-1)*360+d2.month*30+d2.day;
if((a-b)>0)
return a-b;
else
return b-a;
}
void Date:: display()
{
cout<<year<<"/"<<month<<"/"<<day<<endl;
}
int main()
{
Date d1(2019,4,10),d2(2019,5,12),d3,d4;
cout<<"两日期相差天数:";
int d=d1*d2;
cout<<d<<endl;
cout<<"2019/4/10加上1361天后的日期为:";
d4=Date(1361);
d3=d1+d4;
d3.display();
cout<<"2019/4/10减去1361天后的日期为:";
d4=Date(1361);
d3=d1-d4;
d3.display();
return 0;
}