Single chain reverse time complexity of O (n) - Code World

Single chain reverse time complexity of O (n)

Others 2019-07-06 06:56:05 views: null

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Origin blog.csdn.net/shen19960603/article/details/90489814

Single chain reverse time complexity of O (n)

Reverse interval list, the node K between each single linked list in reverse order, to print out a new list; finally less than the number of nodes K need not reverse; request time complexity is O (n), the additional space complexity is O (1) .

Linked list merge (time complexity O(n))

Numbers that disappear (requires time complexity O(N))

[Algorithm Brush] [Linked List] Reverse the specified interval in the linked list: Reverse the interval between the m position and the n position of a linked list with the number of nodes as size, requiring time complexity O(n), space complexity) O(1 ).

Time complexity T(n) = O( f(n)) and space complexity S(n) = O( f(n))

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Appreciated that the time complexity of the algorithm, O (1), O (n), O (log2n), O (n ^ 2)

Appreciated that the time complexity of the algorithm, O (1), O (n), O (log2n), O (n ^ 2)

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Leetcode Interview Question 50. The first character that appears only once [time complexity is O (n), space complexity is O (26)]

Given an array of 0, 1, 2, arrange 0, 1, 2 in order, the space complexity is O(1), and the time complexity is O(n)

[Smart Solution] Count the number of occurrences of each element of an unordered array - time complexity O(n), space complexity O(1)

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Given an array of length N, find that appear more than n / number 2, n / 3, the required time complexity O (n), the spatial complexity is O (1)

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