LeetCode 1108. Defanging an IP Address (IP Address invalidated)

Topic label: String

  Title gave us a set of ip address, let's. Become [.], This problem can replace, but to do so, did not seem to make sense. We still go about the array, specifically to see the code.

 

Java Solution:

Runtime:  0 ms, faster than 100 % 

Memory Usage: 34 MB, less than 100 %

Completion Date: 08/01/2019

Key: n / a

class Solution {
    public String defangIPaddr(String address) {
        char[] charsArr = address.toCharArray();
        StringBuilder sb = new StringBuilder();
        
        for(char c : charsArr) {
            if(c == '.') 
                sb.append("[.]");
            else
                sb.append(c);
        }
        
        return sb.toString();
    }
}

References: n / a

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Topic Source: https: //leetcode.com/

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Origin www.cnblogs.com/jimmycheng/p/11300831.html