20194713+ automatically generates four arithmetic problem first edition report

1. Requirements Analysis:

  Java or C language used to complete a calculation program automatically generates four questions in order to simplify the calculation process, to improve efficiency.

2. Functional Design

(1) automatically generates four arithmetic operation of Equation 2 number less than 10 100 (+ - * /), operation results are required within 100

(2) discarding duplicates equation. = 2 + 3 + 3 = 2 and Equation 2 is repeated and 3 + = 3 + 2 = not repeated formula

Number (3) title can be customized

(4) parameters can be controlled

          Whether to include multiplication and division

          Controllable range values ​​of the operands (e.g., operands within 100 or within 1000)

          Whether operands containing negative　　　　

  (5) generating operation to an external file title stored in result.txt

3. Design and Implementation

    With the c programming language, the c-free main function implemented by

4. Run the test

 

5. Insert Code

 1 main()
 2 {    
 3     
 4     int rand_1,rand_2,rand_3,i;
 5     int rand_4,store=0;
 6     int number,temp,number_1;
 7     srand((unsigned)time(NULL));//生成随机种子 
 8     printf("请输入您要生成题目的数量\n");
 9     scanf("%d",&number);//定义输入控制循环变量 
10     printf("0 代表加减乘除随机生成\n1 代表加\n2 代表减\n3 代表乘\n4 代表除\n");
11     scanf("%d",&temp);//选项 
12     number_1=number;
13     while(number>=1)
14     {    
15     
16             switch(temp)//选项内容 
17         {
18             case 0: number--;break;//退出循环 
19                 
20             
21             case 1: rand_1= rand()%100;    //随机种子 
22                     rand_2= rand()%100;
23                     rand_3=rand_1+rand_2;//运算 
24                     if(rand_3<1000)
25                         number--;//计次 
26                         else
27                         break; 
28                     printf("%d+%d=%d\n",rand_1,rand_2,rand_3);
29                     number_1=0;
30                     break;//退出循环  
31            
32             case 2: rand_1= rand()%100;    
33                     rand_2= rand()%100;
34                     rand_3=rand_1-rand_2;
35                     if(rand_3<1000)
36                         number--;
37                         else
38                         break;
39                     printf("%d-%d=%d\n",rand_1,rand_2,rand_3);
40                      number_1=0;
41                     break; 

 1 if(number_1>=1)//查看时候进行上面的算法满足则进行 
 2 {
 3     
 4     
 5     while(1)//死循环 
 6 {        
 7             rand_4=rand()%100;
 8             rand_4=rand_4/10;//生成随机数 
 9 //+++++++++++++++++++++++++++++++++++++++++++++++++++++++++
10             if(rand_4>=0&&rand_4<=3)//产生随机选择四个运算 
11 {            
12             
13             switch(rand_4)
14 {
15     case 0:
16                     rand_1= rand()%100;    //此处同上 
17                     rand_2= rand()%100;
18                     rand_3=rand_1+rand_2;
19                     if(rand_3<1000)
20                         store++;
21                        else
22                         break;
23                     printf("%d+%d=%d\n",rand_1,rand_2,rand_3);
24                     break;

6.总结

程序编写的不太完善，也有好多不懂得地方，以后多加改正，认真学习。

7.PSP

 

PSP2.1	任务内容	计划共完成需要的时间(min)	实际完成需要的时间(min)
Planning	计划	20	20
Estimate	·  估计这个任务需要多少时间，并规划大致工作步骤	30	40
Development	开发	110	150
Analysis	需求分析 (包括学习新技术)	10	15
Design Spec	·  生成设计文档	10	15
Design Review	·  设计复审 (和同事审核设计文档)	10	15
Coding Standard	代码规范 (为目前的开发制定合适的规范)	10	15
Design	具体设计	20	30
Coding	具体编码	60	120
Code Review	·  代码复审	10	15
Test	·  测试（自我测试，修改代码，提交修改）	15	30
Reporting	报告	20	30
Test Report	·总结改进	10	20