PHP code articles (six) - how to meet the conditions according to the person who invited members of the superior query id

He said that if there is a membership table, each member has to invite a person from_id field (record of the member who invited), know that a member id, and now need to check whether a particular member of the member of subordinates.

Table is as follows:

 

 First, the needs of the moment

　　1, we need to know members id5 Zhao money, if Joe Smith is a member id affiliated members.

　　2, Code of ideas, check up from the lower levels, because a person can only have one parent. Recursive query, the query to a higher level, to judge, to meet is returned. Not satisfied to get a new higher level, research has been to meet or query, there is no supervisor or member, complete the membership records of all inquiries.

　　3, as follows

/**
 * Determine whether the members of the lower level is another member
 * @Param [type] $ member_id system head id
 * @param  [type] $other_member_id     下级id
 * @return [type] 
 * / 
Function getInfo ( $ member_id , $ other_member_id ) {
     // lower member information id 
    $ from_info = $ the this -> findMemberData ([ 'id' => $ other_member_id ], 'id, from_id' );
     // Member of invite people id assignment 
    $ uid = $ from_info [ 'from_id' ];
     the while ( $ uid > 0) { // have to invite people to judge, that is to meet the return true; otherwise up to research, has been found not invite people up to 
        $ from_info = $ the this -> findMemberData ([ 'ID' => $ UID ], 'ID, from_id' );
         IF ( $ from_info['from_id'] == $member_id){
            return 1;
        } The else {
             // not satisfied, the re-assignment 
            $ UID = $ from_info [ 'from_id' ];
        }
    }
    return 0;
}