Magic licensing issues - python achieve

Problem Description

Magician hands of A, 2,3 ...... J, Q, K thirteen spades playing cards. Before performing magic, magicians have stacked them in a certain order good (have color side down) magic show for the process: the beginning, the magician number 1, and then goes to the top of the card turned over , spades a; then place it on your desktop; second, the number of magicians 1,2; the first card into the bottom card, the second card is turned over, just spades 2; the third time, the magician number 1,2,3; 1,2-card will turn into the bottom of these cards, the third card is turned over just spades 3; ...... until all cards have turned out so far. the original order of the cards is to ask how.

Correct result: [1, 8, 2, 5, 10, 3, 12, 11, 9, 4, 7, 6, 13]

solution

1. List

def solution_list():
    pokers = [0 for _ in range(13)]         # 初始化
    count = len(pokers)                     # 纸牌总数
    index = -1

    for num in range(1, 14):
        i = 0                               # 计数
        while i < num:
            index = (index + 1) % count     # 索引向前一步(可循环)
            if pokers[index] == 0:          # 当前元素为0时才计数, 不为0则跳过
                i += 1
        pokers[index] = num

    print('#' * 50)
    print(f'\n牌组: {pokers}\n')
    print('#' * 50)

2. round robin list

class Node:
    """节点"""

    def __init__(self, value):
        self.data = value
        self.next = None

    def __repr__(self):
        return f'Node: {self.data}'


class CircularLinkedList:
    """单循环链表"""
    def __init__(self):
        self.rear = None    # 尾节点

    def is_empty(self):
        return self.rear is None

    def append(self, elem):
        """尾插法"""
        temp = Node(elem)
        if self.rear is None:
            temp.next = temp
            self.rear = temp
        else:
            temp.next = self.rear.next
            self.rear.next = temp
            self.rear = temp
            
    def print_all(self):
        """
        按顺序打印全部节点
        """
        if self.is_empty():
            return
        p = self.rear.next      # 取得头部节点
        print('Head', end='')
        while True:
            print('-->', p.data, end='')
            if p is self.rear:      # 到达尾部停止
                break
            p = p.next
        print('-->Finish')


def solution_circular_linked_list():
    pokers = CircularLinkedList()
    for _ in range(13):
        pokers.append(0)

    temp = pokers.rear
    for num in range(1, 14):
        i = 0
        while i < num:
            temp = temp.next
            if temp.data == 0:
                i += 1
        temp.data = num

    print('#' * 50)
    print('\n牌组: ')
    pokers.print_all()
    print('\n' + '#' * 50)