An easy problem
Subject description:
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6 R 1 P 2 G 3 r 1 p 2 g 3Sample Output
19 18 10 -17 -14 -4
By the answer:
#include<iostream>
using namespace std;
int f(char c){
int res;
if(c>='A'&&c<='Z') //当c为大写字母
res = c-'A'+1;
else //当c为小写字母
res = 'a'-c-1;
return res;
}
int main(){
int t,i;
cin>>t;
for(i=0;i<t;i++){
char x;
int y,result;
cin>>x>>y;
result = f(x);
cout<<result+y<<endl;
}
return 0;
}