Element number acquired by the enumerate, then the Boolean value obtained by the filter ID, then according to the Boolean value as a determination condition, the list elements of the same formula of the type taken out. code show as below:
lst = ['beep','boop','foo','bar']
filters = [True,False,False,True]
def bifurcate(lst,filters):
return [
[ x for i,x in enumerate(lst) if filters[i]==True],
[ x for i,x in enumerate(lst) if filters[i]==False]
]
print(bifurcate(lst,filters))
Output:
[['beep', 'bar'], ['boop', 'foo']]
[Finished in 0.6s]
We can also use the function method to implement filtering capabilities, as long as attention is the core of our judgment there is a Boolean expression for the if statement.
def bifurcate(lst,fn):
return[
[ x for x in lst if fn(x)],
[ x for x in lst if not fn(x)]
]
lst = ['up','Python','umbrella','allan']
results = bifurcate(lst, lambda x: x[0] == 'u')
print(results)
Output is as follows:
[['up', 'umbrella'], ['Python', 'allan']]
[Finished in 0.6s]
