https://leetcode-cn.com/problems/replace-elements-with-greatest-element-on-right-side/
To give you an array arr, you replace each element with the largest element to its right, if it is the last element, replace it with -1.
After all replacement operation, please return this array.
Example:
Input: arr = [17,18,5,4,6,1]
Output: [18,6,6,6,1, -1]
prompt:
1 <= arr.length <= 10^4
1 <= arr[i] <= 10^5
Reverse traversal, with the greatest attention is the replacement of the right elements, excluding itself
class Solution {
public:
vector<int> replaceElements(vector<int>& arr) {
int len = arr.size();
int maxn = arr[len - 1];
arr[len - 1] = -1;
for(int i = (len - 2); i >= 0; --i)
{
int tmp = maxn;
maxn = max(maxn, arr[i]);
arr[i] = tmp;
}
return arr;
}
};