#include <stdio.h>
#include <math.h>
void main() {
double x, t, s = 0;
int i = 0;
scanf("%lf", &x);
t = x;
while (fabs(t) >= 1e-6) {
s += t;
i++;
t = -t * x * x / (2 * i) / (2 * i + 1);
}
printf("%.2lf", s);
}
Seeking sinx values: to approximate sinx according to the following equation, an absolute value of the accumulated required until the time is less than 1e-6.
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Origin blog.csdn.net/qq_38490457/article/details/104738006
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