List
create
# Way a l1 = [1,2, 'taibai' ]
# Second way l2 = list ( 'fdhkjdakgnkagankjf')
Print (L1, L2) # will be an element within a string are spaced apart [ 'f', 'd' , 'h', 'k', 'j', 'd', 'a', 'k' , 'g', 'n' , 'k', 'a', 'g', 'a', 'n', 'k', 'j', 'f']
# Three ways: list comprehensions
CRUD
= L3 [ ' Taibai ' , ' Egon ' , ' xiaofeng ' , ' Yanlong ' ] Print (len (L3))
increase
append: Add
. 1 l3.append ( ' XX ' ) Print (L3) # Example: entering new Employee Name
2
. 3 the while . 1 :
. 4 . 5 name = INPUT ( " Please enter the employee performance: (Q q or quit the program) ' )
. 6 . 7 IF name.upper () == ' Q ' : BREAK . 8 . 9 l3.append (name)
10 . 11 Print (L3)
insert insert
1 l3.insert(2,'xxx')
2 print(l3)
#extend with additional iterations
l3.extend ( ' ABCD ' ) # string character smallest element
l3.extend ([ ' Alex ' , 1,2]) # list within the list of elements as the minimum element
Print (L3)
delete
remove
1 # Delete accordance element
2
. 3 l3.remove ( ' Egon ' )
. 4 Print (L3)
pop
# According to the index delete
l3.pop ( -2) # POP index is not specified, the default delete the last
Print (L3)
clear
# Empty elements in a list
l3.clear()
print(l3)
of the
1 # remove by index
2
. 3 del L3 [-1 ]
. 4 Print (L3)
. 5
. 6 # deleted according to step a slice
. 7
. 8 del L3 [:: 2 ]
. 9 Print (L3)
change
1 # according to the index change value
2
. 3 L3 [0] = ' nanshen '
. 4 Print (L3)
. 5
. 6 # accordance slice change value (understanding)
. 7
. 8 L3 [1:] = ' fkkdfaj '
. 9 Print (L3)
10
. 11 # according slice (step Learn)
12 is
13 is L3 [:: 2] = ' ABC '
14 Print (L3)
check
1 for i in l3:
2 print(i)