题目内容：
某班有最多不超过30人（具体人数由键盘输入）参加某门课程的考试，用二维字符数组作函数参数编程实现如下菜单驱动的学生成绩管理系统：
（1）录入每个学生的学号、姓名和考试成绩；
（2）计算课程的总分和平均分；
（3）按成绩由高到低排出名次表；
（4）按成绩由低到高排出名次表；
（5）按学号由小到大排出成绩表；
（6）按姓名的字典顺序排出成绩表；
（7）按学号查询学生排名及其考试成绩；
（8）按姓名查询学生排名及其考试成绩；
（9）按优秀（90~ 100）、良好（80~ 89）、中等（70~ 79）、及格（60~ 69）、不及格（0~ 59）5个类别，统计每个类别的人数以及所占的百分比；
（10）输出每个学生的学号、姓名、考试成绩。
要求程序运行后先显示如下菜单，并提示用户输入选项：
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please enter your choice:
然后，根据用户输入的选项执行相应的操作。
请按照下面的定义及函数原型编程：
#define MAX_LEN 10 /* 字符串最大长度 /
#define STU_NUM 30 / 最多的学生人数 */
int Menu(void);
void ReadScore(long num[], char name[][MAX_LEN], float score[], int n);
void AverSumofScore(float score[], int n);
void SortbyScore(long num[], char name[][MAX_LEN], float score[], int n,
int (*compare)(float a, float b));
int Ascending(float a, float b);
int Descending(float a, float b);
void SwapFloat(float *x, float *y);
void SwapLong(long *x, long *y);
void SwapChar(char x[], char y[]);
void AsSortbyNum(long num[], char name[][MAX_LEN], float score[], int n);
void SortbyName(long num[], char name[][MAX_LEN], float score[], int n);
void SearchbyNum(long num[], char name[][MAX_LEN], float score[], int n);
void SearchbyName(long num[], char name[][MAX_LEN], float score[], int n);
void StatisticAnalysis(float score[], int n);
void PrintScore(long num[], char name[][MAX_LEN], float score[], int n) ;
程序运行结果示例：
Input student number(n<30):
6↙
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
1↙
Input student’s ID, name and score:
11003001↙
lisi↙
87↙
11003005↙
heli↙
98↙
11003003↙
ludi↙
75↙
11003002↙
dumo↙
48↙
11003004↙
zuma↙
65↙
11003006↙
suyu↙
100↙
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
2↙
sum=473,aver=78.83
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
3↙
Sort in descending order by score:
11003006 suyu 100
11003005 heli 98
11003001 lisi 87
11003003 ludi 75
11003004 zuma 65
11003002 dumo 48
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
4↙
Sort in ascending order by score:
11003002 dumo 48
11003004 zuma 65
11003003 ludi 75
11003001 lisi 87
11003005 heli 98
11003006 suyu 100
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
5↙
Sort in ascending order by number:
11003001 lisi 87
11003002 dumo 48
11003003 ludi 75
11003004 zuma 65
11003005 heli 98
11003006 suyu 100
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
6↙
Sort in dictionary order by name:
11003002 dumo 48
11003005 heli 98
11003001 lisi 87
11003003 ludi 75
11003006 suyu 100
11003004 zuma 65
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
7↙
Input the number you want to search:
11003004↙
11003004 zuma 65
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
8↙
Input the name you want to search:
heli↙
11003005 heli 98
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
9↙
<60 1 16.67%
60-69 1 16.67%
70-79 1 16.67%
80-89 1 16.67%
90-99 1 16.67%
100 1 16.67%
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
10↙
11003002 dumo 48
11003005 heli 98
11003001 lisi 87
11003003 ludi 75
11003006 suyu 100
11003004 zuma 65
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
11↙
Input error!
Management for Students’ scores
1.Input record
2.Caculate total and average score of course
3.Sort in descending order by score
4.Sort in ascending order by score
5.Sort in ascending order by number
6.Sort in dictionary order by name
7.Search by number
8.Search by name
9.Statistic analysis
10.List record
0.Exit
Please Input your choice:
0↙
End of program!
代码实现
#include <stdio.h>
#include <string.h>
#define MAX_LEN 10 /* 字符串最大长度 */
#define STU_NUM 30 /* 最多的学生人数 */
int Menu(void); /*输出题设菜单并输入选择*/
void ReadScore(long num[], char name[][MAX_LEN], float score[], int n); /*选项1 录入每个学生的学号、姓名和考试成绩*/
void AverSumofScore(float score[], int n); /*选项2 计算课程的总分和平均分*/
void SortbyScore(long num[], char name[][MAX_LEN], float score[], int n,int (*compare)(float a, float b)); /*选项3.4 按成绩排出名次表*/
int Ascending(float a, float b); /*返回a>b是否为真*/
int Descending(float a, float b); /*返回a<b是否为真*/
void SwapFloat(float *x, float *y); /*转换*x,*y对应的值*/
void SwapLong(long *x, long *y); /*转换*x,*y对应的值*/
void SwapChar(char x[], char y[]); /*转换x[],y[]对应的值*/
void AsSortbyNum(long num[], char name[][MAX_LEN], float score[], int n); /*选项5 按学号由小到大排出成绩表*/
void SortbyName(long num[], char name[][MAX_LEN], float score[], int n); /*选项6 按姓名的字典顺序排出成绩表*/
void SearchbyNum(long num[], char name[][MAX_LEN], float score[], int n); /*选项7 按学号查询学生排名及其考试成绩*/
void SearchbyName(long num[], char name[][MAX_LEN], float score[], int n); /*选项8 按姓名查询学生排名及其考试成绩*/
void StatisticAnalysis(float score[], int n); /*选项9 输出百分比*/
void PrintScore(long num[], char name[][MAX_LEN], float score[], int n); /*输出每个学生的学号、姓名和考试成绩*/
int main()
{
long num[STU_NUM];
float score[STU_NUM];
char name[STU_NUM][MAX_LEN];
int n, co;
printf("Input student number(n<30):\n");
scanf("%d", &n);
while(1)
{
co=Menu();
switch(co)
{
case 1:
ReadScore(num, name, score, n);
break;
case 2:
AverSumofScore(score, n);
break;
case 3:
SortbyScore(num, name, score, n, Descending);
printf("Sort in descending order by score:\n");
PrintScore(num, name, score, n);
break;
case 4:
SortbyScore(num, name, score, n, Ascending);
printf("Sort in ascending order by score:\n");
PrintScore(num, name, score, n);
break;
case 5:
AsSortbyNum(num, name, score, n);
printf("Sort in ascending order by number:\n");
PrintScore(num, name, score, n);
break;
case 6:
SortbyName(num, name, score, n);
printf("Sort in dictionary order by name:\n");
PrintScore(num, name, score, n);
break;
case 7:
SearchbyNum(num, name, score, n);
break;
case 8:
SearchbyName(num, name, score, n);
break;
case 9:
StatisticAnalysis(score, n);
break;
case 10:
PrintScore(num, name, score, n);
break;
case 0:
printf("End of program!");
exit(0);
default :
printf("Input error!\n");
}
}
}
int Menu(void) /*输出题设菜单并输入选择*/
{
int co;
printf("Management for Students' scores\n\
1.Input record\n\
2.Caculate total and average score of course\n\
3.Sort in descending order by score\n\
4.Sort in ascending order by score\n\
5.Sort in ascending order by number\n\
6.Sort in dictionary order by name\n\
7.Search by number\n\
8.Search by name\n\
9.Statistic analysis\n\
10.List record\n\
0.Exit\n\
Please Input your choice:\n");
scanf("%d", &co);
return co;
}
void ReadScore(long num[], char name[][MAX_LEN], float score[], int n) /*选项1 录入每个学生的学号、姓名和考试成绩*/
{
int i;
printf("Input student's ID, name and score:\n");
for(i=0; i<n; i++)
{
scanf("%ld%s%f", &num[i], name[i], &score[i]);
}
}
void AverSumofScore(float score[], int n) /*选项2 计算课程的总分和平均分*/
{
float sum=0;
int i;
for(i=0; i<n; i++)
{
sum+=score[i];
}
printf("sum=%.0f,aver=%.2f\n", sum, sum/n);
}
void SortbyScore(long num[], char name[][MAX_LEN], float score[], int n,int (*compare)(float a, float b)) /*选项3.4 按成绩排出名次表*/
{
int i, j;
for(i=0; i<n-1; i++)
{
for(j=i+1; j<n; j++)
{
if((*compare)(score[i], score[j]))
{
SwapFloat(&score[i], &score[j]);
SwapChar(name[i], name[j]);
SwapLong(&num[i], &num[j]);
}
}
}
}
int Ascending(float a, float b) /*返回a>b是否为真*/
{
return a>b;
}
int Descending(float a, float b) /*返回a<b是否为真*/
{
return a<b;
}
void SwapFloat(float *x, float *y) /*转换*x,*y对应的值*/
{
float temp;
temp=*x;
*x=*y;
*y=temp;
}
void SwapLong(long *x, long *y) /*转换*x,*y对应的值*/
{
long temp;
temp=*x;
*x=*y;
*y=temp;
}
void SwapChar(char x[], char y[]) /*转换x[],y[]对应的值*/
{
char temp[MAX_LEN];
strcpy(temp, x);
strcpy(x, y);
strcpy(y, temp);
}
void AsSortbyNum(long num[], char name[][MAX_LEN], float score[], int n) /*选项5 按学号由小到大排出成绩表*/
{
int i, j;
for(i=0; i<n-1; i++)
{
for(j=i+1; j<n; j++)
{
if(num[i]>num[j])
{
SwapFloat(&score[i], &score[j]);
SwapChar(name[i], name[j]);
SwapLong(&num[i], &num[j]);
}
}
}
}
void SortbyName(long num[], char name[][MAX_LEN], float score[], int n) /*选项6 按姓名的字典顺序排出成绩表*/
{
int i, j;
for(i=0; i<n-1; i++)
{
for(j=i+1; j<n; j++)
{
if(strcmp(name[i], name[j])>0)
{
SwapFloat(&score[i], &score[j]);
SwapChar(name[i], name[j]);
SwapLong(&num[i], &num[j]);
}
}
}
}
void SearchbyNum(long num[], char name[][MAX_LEN], float score[], int n) /*选项7 按学号查询学生排名及其考试成绩*/
{
long se;
int i, t=0;
printf("Input the number you want to search:\n");
scanf("%ld", &se);
for(i=0; i<n; i++)
{
if(num[i]==se)
{
printf("%ld\t%s\t%.0f\n", num[i], name[i], score[i]);
t=1;
}
}
if(t==0)
{
printf("Not found!\n");
}
}
void SearchbyName(long num[], char name[][MAX_LEN], float score[], int n) /*选项8 按姓名查询学生排名及其考试成绩*/
{
char se[MAX_LEN];
int i, t=0;
printf("Input the name you want to search:\n");
scanf("%s", se);
for(i=0; i<n; i++)
{
if(strcmp(se, name[i])==0)
{
printf("%ld\t%s\t%.0f\n", num[i], name[i], score[i]);
t=1;
}
}
if(t==0)
{
printf("Not found!\n");
}
}
void StatisticAnalysis(float score[], int n) /*选项9 输出百分比*/
{
int d1, d2, d3, d4, d5, d6, i;
for(i=0, d1=d2=d3=d4=d5=d6=0; i<n; i++)
{
if(score[i]<60){
d1++;}
else if(score[i]<70){
d2++;}
else if(score[i]<80){
d3++;}
else if(score[i]<90){
d4++;}
else if(score[i]<100){
d5++;}
else{
d6++;}
}
printf("<60\t%d\t%.2f%%\n", d1, 100*(float)d1/n);
printf("%d-%d\t%d\t%.2f%%\n", 60, 69, d2, 100*(float)d2/n); /*这里按题意应该用循环的，但是用了有点麻烦*/
printf("%d-%d\t%d\t%.2f%%\n", 70, 79, d3, 100*(float)d3/n);
printf("%d-%d\t%d\t%.2f%%\n", 80, 89, d4, 100*(float)d4/n);
printf("%d-%d\t%d\t%.2f%%\n", 90, 99, d5, 100*(float)d5/n);
printf("%d\t%d\t%.2f%%\n", 100, d6, 100*(float)d6/n);
}
void PrintScore(long num[], char name[][MAX_LEN], float score[], int n) /*输出每个学生的学号、姓名和考试成绩*/
{
int i;
for(i=0; i<n; i++)
{
printf("%ld\t%s\t%.0f\n", num[i], name[i], score[i]);
}
}
