LeetCode---40. Combination Sum II

题目

给出一个数组和目标值,找出所有的组合,使得组合里面元素的和为目标值。注意:原数组可能有重复元素;数组中的元素在组合里只能出现一次。如:

Example 1:

Input: candidates = [10,1,2,7,6,1,5], target = 8,
A solution set is:
[
[1, 7],
[1, 2, 5],
[2, 6],
[1, 1, 6]
]
Example 2:

Input: candidates = [2,5,2,1,2], target = 5,
A solution set is:
[
[1,2,2],
[5]
]

Python题解

class Solution(object):
    def combinationSum2(self, candidates, target):
        """
        :type candidates: List[int]
        :type target: int
        :rtype: List[List[int]]
        """
        candidates.sort()
        path, res = [], []
        self.dfs(candidates, target, 0, path, res)
        return res

    def dfs(self, candidates, target, index, path, res):
        if target < 0:
            return
        if target == 0:
            res.append(path[:])
        for i in range(index, len(candidates)):
            if i > index and candidates[i] == candidates[i - 1]:
                continue
            self.dfs(candidates, target - candidates[i], i + 1, path + [candidates[i]], res)

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转载自blog.csdn.net/leel0330/article/details/80492492