牛客网数据库SQL实战32—— 将employees表的所有员工的last_name和first_name拼接起来作为Name
题目描述
将employees表的所有员工的last_name和first_name拼接起来作为Name，中间以一个空格区分
CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
输入描述:
无
输出描述:
| Name |
|---|
| Facello Georgi |
| Simmel Bezalel |
| Bamford Parto |
| Koblick Chirstian |
| Maliniak Kyoichi |
| Preusig Anneke |
| Zielinski Tzvetan |
| Kalloufi Saniya |
| Peac Sumant |
| Piveteau Duangkaew |
| Sluis Mary |
我的解答
select last_name||" "||first_name as Name
from employees
试了下concat，失败了，编辑器不支持，只能使用通用语法
我觉得最好的答案
MySQL、SQL Server、Oracle等数据库支持CONCAT方法，
而本题所用的SQLite数据库只支持用连接符号"||"来连接字符串
CONCAT方法：
select CONCAT(CONCAT(last_name," "),first_name) as name from employees
或者
select CONCAT(last_name," "，first_name) as name from employees
本题中使用：
select last_name||" "||first_name as name from employees
