C++求输入A和B的最小公倍数

#include <iostream>
using namespace std;

int getMaxCommonDivisor(int a, int b)
{
	int t;
	while (1)
	{
		if (a < b)
		{
			t = a;
			a = b;
			b = t;
		}
		if (b == 0)
		{
			return a;
			break;
		}
		t = b;
		b = a%b;
		a = t;
	}
}
int main()
{
	int a, b,c;
	cin >> a >> b;
	c = getMaxCommonDivisor(a, b);
	a = a*b / c;
	cout << a;
    return 0;
}


1.最小公倍数 = 两数相乘/两数的最大公约数;
leastCommonMultiple(A,B) = A*B/MaximumCommonMultiple(A,B)
2.欧几里得算法求最大公约数,算法流程图见下,来源:

https://blog.csdn.net/qq_42302831/article/details/88587052

在这里插入图片描述

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转载自blog.csdn.net/weixin_40932028/article/details/105224458