1 小一 98 天津[email protected]
2 小二 88 北极[email protected]
3 小三 78 上海 [email protected]
4 小四 68 深圳 [email protected]
5 小五 58 杭州 [email protected]
6 小六 48 北京 [email protected]
7 小七 99 深圳 [email protected]
8 小八 100 杭州 [email protected]
9 小九 60 陕西 [email protected]
10小紫 70 山西 [email protected]
– 4.
– SELECT * FROM students;
– 5.
– select id,name,score from students where score > 70;
– 6.
– alter table students modify name varchar(50);
– desc students
– 7.
– alter table students add pingjia varchar(20);
– 8.
– update students set score=88 where name=“西三”;
– 9.
– select * from students where score > 80;
– 10.
– update students set score=88+40 where name=“小小”;
– 11.
– select * from students where id in (1,5,7);
– 12.
– select * from students where id between 5 and 8;
– 13.
– select * from students where name=“小小” and score > 60;
– 14.
– select * from students where name=“小小” or score > 90;
– 15.
– select * from students where score is null;
– 16.
– select id,name from students where score is not null;
1001 小一 文员 1013 2000-12-17 8000 0 20
1003 小二 销售员 1013 2000-12-17 8000 0 20
1004 小三 经理 1013 2000-12-17 8000 0 20
1005 小四 销售员 1013 2000-12-17 8000 0 20
1006 小五经理 1013 2000-12-17 8000 0 20
1007 小六 经理 1013 2000-12-17 8000 0 20
1008 小七 分析师 1013 2000-12-17 8000 0 20
1009 小八 董事长 1013 2000-12-17 8000 0 20
1010 小九 销售员 1013 2000-12-17 8000 0 20
1011 中一 文员 1013 2000-12-17 8000 0 20
1012 大二 文员 1013 2000-12-17 8000 0 20
1013 中三 分析师 1013 2000-12-17 8000 0 20
1014 大四 文员 1013 2002-1-23 8000 0 20
1015 中五 文员 1013 2002-1-23 8000 0 20
1002 大六 销售员 1013 2000-12-17 8000 0 20
– 1.
– select * from emp;
– 2.
– select * from emp where ename=“小三”;
– 3.
– select ename,job,sal from emp where ename like “___”;
– 4. 连续范围用比囤 加安得
– select * from emp where empno between 1004 and 1008;
– 5.
– select * from emp where ename=“黄盖” and job=“文员”;
– 6.ALTER
– select * from emp where YEAR(hiredate) > “2001”;
– 7.ALTER
– select * from emp where comm=“0” ;
– 8
– select * from emp;
– rename table yuangong to emp;
– 9
– alter table emp modify ename varchar(40);
– desc emp
– 10
– delete from emp where empno=“1014” and ename=“小小”;
– 11
– select * from emp where empno in (1007,1011,1009);
– 12
– select * from emp where job=“文员” and ename=“小三”;
– 13
– select * from emp where year(hiredate)>“2001”;
创建db_test数据库
1.-- use db_test
2.-- rename table yuangong to emp;
3.-- alter table emp add hobby varchar(50) unique;
4.-- desc emp;
5.-- insret into emp values(1005,“林青霞”,“女”,“架构师”,“1969-12-12”,8000,null,100,“阅读”);
6.-- alter table emp modify sname varchar(40);
7.select * from emp where sid in (1002,1003,1005);
8.update emp set job=“架构师” where job=“高级工程师”;
9.delete from emp where sid=1003 and job=“王五”;
10.update emp set salary=1950-300 where sid=1004;
创建db_test数据库
1.-- rename table teacher to ts;
2.-- insert into teacher values(209,“小石”,“男”,604,4000,“天津”)
- select * from ts;
4.delete from ts where number=201 and sex=“女”;
5.select * from ts where number in (202,205,207);
6.update ts set name=“小文” where number=202;
7.select * from ts order by salary desc;
1.use db_test
2.-- rename table db_test to teacher;
3.insert into teacher values(209,“小青”,“女”,604,4000,“天津”);
4.-- alter table teacher add hobby varchar(50) unique;
5.-- alter table teacher modify depno varchar(40);
6.-- select * from teacher where number between 202 and 206;
7.update emp set sex=“女” where name=“荣荣”;
8.delete from emp where number in (203.205.207);