Problem 22

问题描述:
Using names.txt (right click and 'Save Link/Target As...'), a 46K text file containing over five-thousand first names, begin by sorting it into alphabetical order. Then working out the alphabetical value for each name, multiply this value by its alphabetical position in the list to obtain a name score.

For example, when the list is sorted into alphabetical order, COLIN, which is worth 3 + 15 + 12 + 9 + 14 = 53, is the 938th name in the list. So, COLIN would obtain a score of 938  53 = 49714.

What is the total of all the name scores in the file?


这个题比较简单,主要就是排序!

解决问题:
private static int Partition(String[] array, int begin, int end) {
int positon = -1;
String lastElement = array[end];
int i = begin -1 ;

for(int j=begin; j<=end; j++){
if(array[j].compareTo(lastElement)<0){
i++;
if(i!=j){
String tmp = array[j];
array[j] = array[i];
array[i] = tmp;
}
}
}
if(i+1!=end){
String tmp = array[i+1];
array[i+1] = lastElement;
array[end] = tmp;
}
return i+1;
}


public static void FastSort(String[] array, int begin, int end){
if(begin < end){
int middle = Partition(array, begin, end);
FastSort(array, begin, middle-1);
FastSort(array, middle+1, end);

}
}

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转载自to-zoe-yang.iteye.com/blog/1141951
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