LeetCode（剑指 Offer）- 60. n个骰子的点数

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题目大意：略

解题思路

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AC 代码

• Java

class Solution {
    public double[] dicesProbability(int n) {
        double[] dp = new double[6];
        Arrays.fill(dp, 1.0 / 6.0);
        for (int i = 2; i <= n; i++) {
            double[] tmp = new double[5 * i + 1];
            for (int j = 0; j < dp.length; j++) {
                for (int k = 0; k < 6; k++) {
                    tmp[j + k] += dp[j] / 6.0;
                }
            }
            dp = tmp;
        }
        return dp;
    }
}

• C++

class Solution {
public:
    vector<double> dicesProbability(int n) {
        vector<double> dp(6, 1.0 / 6.0);
        for (int i = 2; i <= n; i++) {
            vector<double> tmp(5 * i + 1, 0);
            for (int j = 0; j < dp.size(); j++) {
                for (int k = 0; k < 6; k++) {
                    tmp[j + k] += dp[j] / 6.0;
                }
            }
            dp = tmp;
        }
        return dp;
    }
};