杭电OJ 2031 进制转换

#include <iostream>
#include <string>
using namespace std;
int main()
{
	int N, R;
	while (cin>>N>>R)
	{
		if (N < 0)
			cout << "-";
		string s;
		N = abs(N);
		while (N > 0)
		{
			int a = N%R;
			if (a >= 10)
				s.push_back(a - 10 + 'A');
			else
				s.push_back(a  + '0');
			N /= R;
		}
		for (int i = s.size() - 1; i >= 0; i--)
			cout << s[i];
		cout << endl;
	}
	return 0;
}

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转载自blog.csdn.net/fuwu4087/article/details/80511836