【ACM】杭电OJ 2031

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/CSDN___CSDN/article/details/84334969
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <cstdlib>
using namespace std;
const int maxn = 10000;
int a[maxn];
int main ()
{
	int m,n,k,i;
	while(scanf("%d%d",&n,&m)==2)
	{
		memset(a,0,sizeof(a));
		if(n<0)	
		{
			printf("-");
			n=abs(n);
		}
		k=-1;
		while(n)
		{
			a[++k]=n%m;
			n/=m;
		}
		if(m>10)
		{
			for(i=k;i>=0;i--)
			{
				if(a[i]>=10)
				{
					switch(a[i])
					{
					case 10:printf("A");break;
					case 11:printf("B");break;
					case 12:printf("C");break;
					case 13:printf("D");break;
					case 14:printf("E");break;
					case 15:printf("F");break;
					}
				}
				else
					printf("%d",a[i]);
			}
			printf("\n");
		}
		else
		{
			for(i=k;i>=0;i--)
			{
				printf("%d",a[i]);
			}
			printf("\n");
		}
	}
	return 0;
}

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转载自blog.csdn.net/CSDN___CSDN/article/details/84334969