判断LocalDateTime 时间大小
即返回long 就是判断long 即可 调用
Duration.between()
LocalDateTime time1= LocalDateTime.of(2018, 7, 9, 0, 0); //time1 LocalDateTime time2 = LocalDateTime.now();//time2
Duration duration = Duration.between(time1, time2); Long timeRange = duration.toMillis(); //转化long
if (timeRange > 0) {
//time1 > time2 } else {
//time1 < time2
}
时间增加 小时 天 月 年 还有很多不一一说明 具体之说这几个
LocalDateTime time = LocalDateTime.now();
LocalDateTime increaseTime = time.plusHours(1);//增加一小时
LocalDateTime increaseTime = time.plusDays(1);//增加一天
LocalDateTime increaseTime = time.plusMonths(1);//增加一月
LocalDateTime increaseTime = time.plusYears(1);//增加一年