题目描述:
Find the total area covered by two rectilinear rectangles in a 2D plane.
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.
Example:
Input: A = -3, B = 0, C = 3, D = 4, E = 0, F = -1, G = 9, H = 2
Output: 45
Note:
Assume that the total area is never beyond the maximum possible value of int.
计算两个矩形重叠覆盖的面积,可以分别计算两个矩形的面积再减去重复的面积。
class Solution {
public:
int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
int sum=(C-A)*(D-B)+(G-E)*(H-F);
if(A>=G||C<=E||D<=F||B>=H) return sum;
else return sum-(min(C,G)-max(A,E))*(min(D,H)-max(B,F));
}
};