项目需要android开机自动启动一个app的界面,网上找了些资料,证实可用:
首先是在你要启动的app的
AndroidManifest.xml文件里面加下面一段代码(注意是加在application标签内):
<
receiver
android:enabled
="true"
android:name
=".BootUpReceiver"
android:permission ="android.permission.RECEIVE_BOOT_COMPLETED" >
< intent-filter >
< action android:name ="android.intent.action.BOOT_COMPLETED" />
< category android:name ="android.intent.category.DEFAULT" />
</ intent-filter >
</ receiver >
< uses-permission android:name ="android.permission.RECEIVE_BOOT_COMPLETED" />
android:permission ="android.permission.RECEIVE_BOOT_COMPLETED" >
< intent-filter >
< action android:name ="android.intent.action.BOOT_COMPLETED" />
< category android:name ="android.intent.category.DEFAULT" />
</ intent-filter >
</ receiver >
< uses-permission android:name ="android.permission.RECEIVE_BOOT_COMPLETED" />
之后在项目里面创建一个
BootUpReceiver的类(
MyActivity是你自己的app的main activity
):
public
class BootUpReceiver
extends BroadcastReceiver{
public void onReceive(Context context, Intent intent) {
Intent i = new Intent(context, MyActivity. class);
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
}
public void onReceive(Context context, Intent intent) {
Intent i = new Intent(context, MyActivity. class);
i.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
context.startActivity(i);
}
}
之后编译运行,再启动系统的时候,app就可以在系统启动完成之后自动运行啦