java访问http并获得json数据解析json数据
需要fastjson-1.1.24.jar
此方法必须访问http请求，访问https需要httpclient
具体方法：
@RequestMapping("geturl.do")
public void geturl(HttpServletResponseresponse){
String url = "http://localhost:8080/Test/getUsers.do?id=1";
//new一个stringbuffer
StringBuffer json = new StringBuffer();
try {
//通过url获得连接
URL u = new URL(url);
URLConnection yc = u.openConnection();
//读取返回的数据
BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream(),"UTF-8"));
String inputline = null;
while((inputline=in.readLine())!=null){
json.append(inputline);
}
in.close();
} catch (Exception e) {
e.printStackTrace();
}
//获得jsonobject
JSONObject jo = JSON.parseObject(json.toString());
JSONObject jo2 = jo.getJSONObject("data");
//获得json数组
JSONArray ja = jo2.getJSONArray("users");
JSONObject jo3 = null;
Users user = null;
for (int i = 0; i < ja.size(); i++) {
jo3 = ja.getJSONObject(i);
user = new Users();
user.setId(jo3.getIntValue("id"));
user.setUsername(jo3.getString("username"));
user.setPassword(jo3.getString("password"));
user.setAge(jo3.getIntValue("age"));
user.setSex(jo3.getIntValue("sex"));
System.out.println(user.getUsername());
}
}