LeetCode笔记-A1-Two Sum

我的解决(暴力遍历):

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> res;
        int k = nums.size();
        for (int i = 0; i < k ; ++i) {
            //if (nums.at(i)>target) continue;
            for (int j = i+1; j < k; ++j) {
                if (nums.at(i)+nums.at(j)==target) {
                    res.push_back(i);
                    res.push_back(j);
                    return res;
                }
            }
        }
    }
};

总结:这个方法没什么技术含量,时间复杂度比较差

参考了LeetCode上的参考解答,使用一趟的哈希表,可以得到时间复杂度更好的结果:

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> res;
        map<int,int> mymap;
        int k = nums.size();
        for (int i = 0; i < k ; ++i) {
            int complement = target - nums[i];
            if (mymap.find(complement)!=mymap.end()&&mymap.at(complement)!=i) {
                res.push_back(i);
                res.push_back(mymap[complement]);
                return res;
            }
            mymap[nums[i]] = i;
        }
    }
};


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转载自blog.csdn.net/ken_for_learning/article/details/79554244
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