009. Python基本数学运算

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Fiza buzz

一、题目描述

要求：输入一个数字，如果数字可以同时被3和5整除，输出“Fizz Buzz”；如果数字可以被3整除，而不可以被5整除，输出“Fizz”；如果数字可以倍5整除不可被3整除，输出“Buzz”；其他情况，把数字转换成字符串类型输出

输入：整数

输出：字符串

示例：

checkio(15) == "Fizz Buzz"
checkio(6) == "Fizz"
checkio(5) == "Buzz"
checkio(7) == "7"

二、解题示例

1. 直接解法

# Your optional code here
# You can import some modules or create additional functions


def checkio(number: int) -> str:
    # Your code here
    # It's main function. Don't remove this function
    # It's using for auto-testing and must return a result for check.

    # replace this for solution
    if number % 3 == 0 and number % 5 == 0:
        return "Fizz Buzz"
    elif number % 3 == 0:
        return "Fizz"
    elif number % 5 == 0:
        return "Buzz"
    else:
        return str(number)

# Some hints:
# Convert a number in the string with str(n)

# These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(15) == "Fizz Buzz", "15 is divisible by 3 and 5"
    assert checkio(6) == "Fizz", "6 is divisible by 3"
    assert checkio(5) == "Buzz", "5 is divisible by 5"
    assert checkio(7) == "7", "7 is not divisible by 3 or 5"
    print("Coding complete!")

2.正则表达式法

checkio=lambda n:("Fizz "*(1-n%3)+"Buzz "*(1-n%5))[:-1]or str(n)