Xamarin实现窗口跳转

btn_bd = FindViewById<Button>(Resource.Id.btn_bd);
btn_bd.Click += (object sender, EventArgs e) =>
{ //弹出窗口
Intent i = new Intent(this, typeof(MainActivity));
this.StartActivity(i);
};

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转载自blog.csdn.net/z1607273131/article/details/81144465