[LeeCode] Shuffle an Array

打乱一个没有重复元素的数组。

示例:

// 以数字集合 1, 2 和 3 初始化数组。
int[] nums = {1,2,3};
Solution solution = new Solution(nums);

// 打乱数组 [1,2,3] 并返回结果。任何 [1,2,3]的排列返回的概率应该相同。
solution.shuffle();

// 重设数组到它的初始状态[1,2,3]。
solution.reset();

// 随机返回数组[1,2,3]打乱后的结果。
solution.shuffle();
class Solution {
public:
    Solution(vector<int> nums):v(nums) {
        
    }
    
    /** Resets the array to its original configuration and return it. */
    vector<int> reset() {
        return v;
    }
    
    /** Returns a random shuffling of the array. */
    vector<int> shuffle() {
        vector<int> result = v;
        for(int i = 0;i < result.size();++i){
            int t = i+ rand() % (result.size() - i);
            swap(result[i],result[t]);
        }
        
        return result;
    }
    
private:
    vector<int> v;
    
};

/**
 * Your Solution object will be instantiated and called as such:
 * Solution obj = new Solution(nums);
 * vector<int> param_1 = obj.reset();
 * vector<int> param_2 = obj.shuffle();
 */



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转载自blog.csdn.net/weixin_37992828/article/details/82469344