181. 超过经理收入的员工

Employee 表包含所有员工,他们的经理也属于员工。每个员工都有一个 Id,此外还有一列对应员工的经理的 Id。

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

给定 Employee 表,编写一个 SQL 查询,该查询可以获取收入超过他们经理的员工的姓名。在上面的表格中,Joe 是唯一一个收入超过他的经理的员工。

+----------+
| Employee |
+----------+
| Joe      |
+----------+

思路:SELF JOIN

方法1:用WHERE 实现

SELECT e1.Name AS Employee
FROM Employee AS e1, Employee AS e2
WHERE (e1.ManagerId = e2.Id) AND (e1.Salary > e2.Salary)

方法1:用JOIN 实现

SELECT e1.Name AS Employee
FROM Employee AS e1 JOIN Employee AS e2
ON (e1.ManagerId = e2.Id) AND (e1.Salary > e2.Salary)

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转载自blog.csdn.net/Scarlett_Guan/article/details/82946165