Python判断某个列表是否是另一个列表的子列表

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/u012111465/article/details/82964726
>>> ls1 = ['sa1','sa5','sa8']
>>> ls2 = ['sa1','sa5','sa8','sa10']
>>> set(ls1).issubset(set(ls2))
True

猜你喜欢

转载自blog.csdn.net/u012111465/article/details/82964726