问题:
1.swagger解决传递json以为参数的方法
2.spring接受实体对象
问题一:
@ApiOperation(httpMethod = "POST",value = "测试能否使用application/x-www-form-urlencoded",consumes="application/x-www-form-urlencoded") @ResponseBody引入consumes参数
问题二:
1.引入依赖,
<!-- swagger --> <dependency> <groupId>io.springfox</groupId> <artifactId>springfox-swagger2</artifactId> <version>2.4.0</version> </dependency> <dependency> <groupId>io.springfox</groupId> <artifactId>springfox-swagger-ui</artifactId> <version>2.4.0</version> </dependency>2.导入ui文件,去官网下一个
3.swagger/index.html中有url中的参数改成你的项目的参数
4.controller中
@RequestMapping(value = "/insertVideo", method = RequestMethod.POST) @ResponseBody @ApiOperation(httpMethod = "POST",value = "上传视屏接口", notes = "上传视屏") public Result<Integer> insertVideo( @RequestBody @ApiParam(name="视屏name",value="视屏对象11") TVideo tVideo ) { System.out.println(Global.getFrontPath()); System.out.println(tVideo.getLongtime()); Result<Integer> result = Result.<Integer>getSucceedInstance(); return result; }5.实体类中
@ApiModel(value="视屏对象") public class TVideo { private Integer videoId; @ApiModelProperty(value="视屏地址",example="/!!!/sss") private String url;